Solutions 13
نویسنده
چکیده
would be a square. One could factor this into primes in Z to see that it is not a square, or hope that it is not a square modulo some relatively small prime. Indeed, modulo 11 it is 2, which is not a square modulo 11 (by brute force, or by Euler’s criterion (using the cyclicness of (Z/11)×) 2(11−1)/2 = −1 mod 11, or by recalling the part of Quadratic Reciprocity that asserts that 2 is a square mod p only for p = ±1 mod 8).
منابع مشابه
Solutions of TEAM Problem #13 Using Integral Equations in a Sequential and Parallel Computing Environment
In this paper a brief discussion of h-type volume integra l formulat ions implemented in GFUNET/CORAL code is given and solutions of TEAM benchmark #13 are shown. GFUNET/CORAL is a general purpose code for 2D and 3D magnetostatics. Solutions of TEAM problem #13 are computed using both a sequential and parallel version of GFUNET/CORAL.
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